What is the inverse of 4ln(x^2+2x+1) ?

The inverse of 4ln(x^2+2x+1) is -1+sqrt(e^{x/4)},-sqrt(e^{x/4)}-1

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inverse of 4ln(x^2+2x+1)

inverse

4 ln (x^{2} + 2 x + 1)

- 1 + e^{\frac{x}{4}}, - e^{\frac{x}{4}} - 1

Solution steps

y = 4 ln (x^{2} + 2 x + 1)

Replace

x

with

y

x = 4 ln (y^{2} + 2 y + 1)

Solve for

y, x = 4 ln (y^{2} + 2 y + 1)

- 1 + e^{\frac{x}{4}}, - e^{\frac{x}{4}} - 1

f (x) = ln (\frac{( 1 - x )}{x})

arccsc (3) x^{2}

f (x) = 5^{\frac{x}{2}} - 7

\frac{x + 8}{x + 3}

y = \frac{4 x + 3}{- 5 x + 5}

What is the inverse of 4ln(x^2+2x+1) ?
The inverse of 4ln(x^2+2x+1) is -1+sqrt(e^{x/4)},-sqrt(e^{x/4)}-1