What is the critical f(x)=160x+((7200)/x) ?

The critical f(x)=160x+((7200)/x) is x=-3sqrt(5),x=3sqrt(5)

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critical f(x)=160x+((7200)/x)

critical points

f (x) = 160 x + (\frac{7200}{x})

x = - 35, x = 35

Solution steps

160 x + \frac{7200}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 35, x = 35, x = 0

Identify critical points not in

f (x)

domain

Domain of

160 x + \frac{7200}{x} : x < 0 or x > 0

160 x + \frac{7200}{x}

is not defined at

x = 0

, therefore:

x = - 35, x = 35

f (x) = \frac{( 5 x + 1 )}{x - 2}

f

f (x) = ln (2 - 3 x)

f (x) = \frac{2}{3} (x + 5)

What is the critical f(x)=160x+((7200)/x) ?
The critical f(x)=160x+((7200)/x) is x=-3sqrt(5),x=3sqrt(5)