What is the inverse of ((2x-1)^2)/e ?

The inverse of ((2x-1)^2)/e is (sqrt(ex)+1)/2 ,(-sqrt(ex)+1)/2

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inverse of ((2x-1)^2)/e

inverse

\frac{( 2 x - 1 ) ^{2}}{e}

\frac{e x + 1}{2}, \frac{- e x + 1}{2}

Solution steps

y = \frac{( 2 x - 1 ) ^{2}}{e}

Replace

x

with

y

x = \frac{( 2 y - 1 ) ^{2}}{e}

Solve for

y, x = \frac{( 2 y - 1 ) ^{2}}{e}

\frac{e x + 1}{2}, \frac{- e x + 1}{2}

f (x) = \frac{3 - 2 x}{5 - x}

h (x) = \frac{x ^{3} + 2}{6}

f (x) = \frac{( x + 4 )}{3 - x}

\frac{1}{s ^{2} + a s}

f (x) = 0.2

What is the inverse of ((2x-1)^2)/e ?
The inverse of ((2x-1)^2)/e is (sqrt(ex)+1)/2 ,(-sqrt(ex)+1)/2