What is the inverse of f(x)=3+sqrt(4x-3) ?

The inverse of f(x)=3+sqrt(4x-3) is (x^2-6x+12)/4

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inverse of f(x)=3+sqrt(4x-3)

inverse

f (x) = 3 + 4 x - 3

\frac{x ^{2} - 6 x + 12}{4}

Solution steps

y = 3 + 4 x - 3

Replace

x

with

y

x = 3 + 4 y - 3

Solve for

y, x = 3 + 4 y - 3

\frac{x ^{2} - 6 x + 12}{4}

4 - 6 (4 - 1)

f (x) = 2 sin (x) - 7

\frac{x - 4 x}{x - 4}

f (x) = \frac{3 x}{5 x - 9}

f (x) = - 5 ln (4 x + 4)

What is the inverse of f(x)=3+sqrt(4x-3) ?
The inverse of f(x)=3+sqrt(4x-3) is (x^2-6x+12)/4