What is the inverse of f(x)=(9-x^2)^{1/2} ?

The inverse of f(x)=(9-x^2)^{1/2} is sqrt(-x^2+9),-sqrt(-x^2+9)

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inverse of f(x)=(9-x^2)^{1/2}

inverse

f (x) = (9 - x^{2})^{\frac{1}{2}}

- x^{2} + 9, - - x^{2} + 9

Solution steps

y = (9 - x^{2})^{\frac{1}{2}}

Replace

x

with

y

x = (9 - y^{2})^{\frac{1}{2}}

Solve for

y, x = (9 - y^{2})^{\frac{1}{2}}

- x^{2} + 9, - - x^{2} + 9

\frac{1}{x - 4} - 6

f (x) = \frac{2}{x - 4} + 1

f (x) = (\frac{x}{2})^{2} + 1

f (x) = (\frac{x}{2})^{2} + 3

y = arctan (\frac{1}{x})

What is the inverse of f(x)=(9-x^2)^{1/2} ?
The inverse of f(x)=(9-x^2)^{1/2} is sqrt(-x^2+9),-sqrt(-x^2+9)