What is the inverse of f(x)=(10x+13)^2 ?

The inverse of f(x)=(10x+13)^2 is (sqrt(x)-13)/(10),(-sqrt(x)-13)/(10)

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inverse of f(x)=(10x+13)^2

inverse

f (x) = (10 x + 13)^{2}

\frac{x - 13}{10}, \frac{- x - 13}{10}

Solution steps

y = (10 x + 13)^{2}

Replace

x

with

y

x = (10 y + 13)^{2}

Solve for

y, x = (10 y + 13)^{2}

\frac{x - 13}{10}, \frac{- x - 13}{10}

f (x) = \frac{( 3 x - 7 ) + 3}{7}

2 x^{2} - 5 x - 1

f (x) = \frac{( 3 x + 4 )}{x - 2}

f (x) = 4 + 2

y = \frac{( x + 2 )}{x + 7}

What is the inverse of f(x)=(10x+13)^2 ?
The inverse of f(x)=(10x+13)^2 is (sqrt(x)-13)/(10),(-sqrt(x)-13)/(10)