What is the inverse of f(x)= 2/3 x^3-7 ?

The inverse of f(x)= 2/3 x^3-7 is cube root of (3x+21)/2

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inverse of f(x)= 2/3 x^3-7

inverse

f (x) = \frac{2}{3} x^{3} - 7

Solution steps

y = \frac{2}{3} x^{3} - 7

Replace

x

with

y

x = \frac{2}{3} y^{3} - 7

Solve for

y, x = \frac{2}{3} y^{3} - 7

84 x^{3}

2^{2 a - 1}

f (x) = 7 e^{x} - 9

f (x) = \frac{7 x + 3}{8} x - 5

f (x) = 4 n - 20

What is the inverse of f(x)= 2/3 x^3-7 ?
The inverse of f(x)= 2/3 x^3-7 is cube root of (3x+21)/2