What is the inverse of f(x)=(2x+1)^3-2 ?

The inverse of f(x)=(2x+1)^3-2 is (\sqrt[3]{x+2}-1)/2

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inverse of f(x)=(2x+1)^3-2

inverse

f (x) = (2 x + 1)^{3} - 2

Solution steps

y = (2 x + 1)^{3} - 2

Replace

x

with

y

x = (2 y + 1)^{3} - 2

Solve for

y, x = (2 y + 1)^{3} - 2

lo g_{10} (x - 5) + 2

f (x) = 60 - 4 x

f (x) = (x - 2) 2 + (y - 1) 2 = 4

lo g_{3} (y + 3) - 2

4 - 3 x^{2}

What is the inverse of f(x)=(2x+1)^3-2 ?
The inverse of f(x)=(2x+1)^3-2 is (\sqrt[3]{x+2}-1)/2