What is the inverse of f(x)=((x+1))/((x+3)) ?

The inverse of f(x)=((x+1))/((x+3)) is (1-3x)/(x-1)

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inverse of f(x)=((x+1))/((x+3))

inverse

f (x) = \frac{( x + 1 )}{( x + 3 )}

\frac{1 - 3 x}{x - 1}

Solution steps

y = \frac{x + 1}{x + 3}

Replace

x

with

y

x = \frac{y + 1}{y + 3}

Solve for

y, x = \frac{y + 1}{y + 3}

\frac{1 - 3 x}{x - 1}

lo g_{10} (x - 5) - 3

f (x) = \frac{1}{7} (x^{3} + 5)

\frac{2 ^{x} - 1}{2 ^{x} + 1}

y = x^{2} + 9, x \leq 0

- x^{2} + 2 x + 5

What is the inverse of f(x)=((x+1))/((x+3)) ?
The inverse of f(x)=((x+1))/((x+3)) is (1-3x)/(x-1)