What is the inverse of f(x)=(2y+1)/(3y-2) ?

The inverse of f(x)=(2y+1)/(3y-2) is (1+2y)/(3y-2)

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inverse of f(x)=(2y+1)/(3y-2)

inverse

f (x) = \frac{2 y + 1}{3 y - 2}

\frac{1 + 2 y}{3 y - 2}

Solution steps

x = \frac{2 y + 1}{3 y - 2}

Replace

y

with

x

y = \frac{2 x + 1}{3 x - 2}

Solve for

x, y = \frac{2 x + 1}{3 x - 2}

\frac{1 + 2 y}{3 y - 2}

f (x) = \frac{15 x}{4 x + 1}

y = \frac{2 + ln ( 4 x + 3 )}{5}

f (x) = \frac{4}{x + 3} - 1

f (x) = 5 + ln (x - 3)

y = 6 x - 13

What is the inverse of f(x)=(2y+1)/(3y-2) ?
The inverse of f(x)=(2y+1)/(3y-2) is (1+2y)/(3y-2)