What is the inverse of f(x)= 1/3 x^2-4 ?

The inverse of f(x)= 1/3 x^2-4 is sqrt(3x+12),-sqrt(3x+12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 1/3 x^2-4

inverse

f (x) = \frac{1}{3} x^{2} - 4

3 x + 12, - 3 x + 12

Solution steps

y = \frac{1}{3} x^{2} - 4

Replace

x

with

y

x = \frac{1}{3} y^{2} - 4

Solve for

y, x = \frac{1}{3} y^{2} - 4

3 x + 12, - 3 x + 12

y = 4 - \frac{1}{( x + 1 ) ^{2}}

f (x) = \frac{2 x + 3}{5 x - 1}, x \neq = \frac{1}{5}

f (x) = 3 - e^{2 x}

\frac{1}{200} (x - 40)

What is the inverse of f(x)= 1/3 x^2-4 ?
The inverse of f(x)= 1/3 x^2-4 is sqrt(3x+12),-sqrt(3x+12)