What is the inverse of y=4-1/((x+1)^2) ?

The inverse of y=4-1/((x+1)^2) is sqrt(-1/(x-4))-1,-sqrt(-1/(x-4))-1

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inverse of y=4-1/((x+1)^2)

inverse

y = 4 - \frac{1}{( x + 1 ) ^{2}}

- \frac{1}{x - 4} - 1, - - \frac{1}{x - 4} - 1

Solution steps

y = 4 - \frac{1}{( x + 1 ) ^{2}}

Replace

x

with

y

x = 4 - \frac{1}{( y + 1 ) ^{2}}

Solve for

y, x = 4 - \frac{1}{( y + 1 ) ^{2}}

- \frac{1}{x - 4} - 1, - - \frac{1}{x - 4} - 1

f (x) = \frac{2 x + 3}{5 x - 1}, x \neq = \frac{1}{5}

f (x) = 3 - e^{2 x}

\frac{1}{200} (x - 40)

x^{2} + 6 x + 7

What is the inverse of y=4-1/((x+1)^2) ?
The inverse of y=4-1/((x+1)^2) is sqrt(-1/(x-4))-1,-sqrt(-1/(x-4))-1