What is the inverse of f(x)=1.5-(1/((0.15x+1))) ?

The inverse of f(x)=1.5-(1/((0.15x+1))) is (-x+0.5)/(0.15x-0.225)

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inverse of f(x)=1.5-(1/((0.15x+1)))

inverse

f (x) = 1.5 - (\frac{1}{( 0.15 x + 1 )})

\frac{- x + 0.5}{0.15 x - 0.225}

Solution steps

y = 1.5 - \frac{1}{0.15 x + 1}

Replace

x

with

y

x = 1.5 - \frac{1}{0.15 y + 1}

Solve for

y, x = 1.5 - \frac{1}{0.15 y + 1}

\frac{- x + 0.5}{0.15 x - 0.225}

y = 2 9^{x}

f (x) = 49 - x^{2}, x \geq 0

sin (4 x^{4})

f (x) = \frac{( x + 1 )}{x - 5}

What is the inverse of f(x)=1.5-(1/((0.15x+1))) ?
The inverse of f(x)=1.5-(1/((0.15x+1))) is (-x+0.5)/(0.15x-0.225)