What is the inverse of f(x)=((x+1))/(x-5) ?

The inverse of f(x)=((x+1))/(x-5) is (1+5x)/(x-1)

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inverse of f(x)=((x+1))/(x-5)

inverse

f (x) = \frac{( x + 1 )}{x - 5}

\frac{1 + 5 x}{x - 1}

Solution steps

y = \frac{x + 1}{x - 5}

Replace

x

with

y

x = \frac{y + 1}{y - 5}

Solve for

y, x = \frac{y + 1}{y - 5}

\frac{1 + 5 x}{x - 1}

\frac{- 4}{5}

f (x) = \frac{5}{4 x - 6} + 5

g (s) = [\frac{25}{s ^{2}} (s^{2} + 4 s + 5)]

f (x) = \frac{1}{3 x ^{8}}

3 - ln (x + 2)

What is the inverse of f(x)=((x+1))/(x-5) ?
The inverse of f(x)=((x+1))/(x-5) is (1+5x)/(x-1)