What is the inverse of-1/((4t-7)^2) ?

The inverse of-1/((4t-7)^2) is (sqrt(-1/t)+7)/4 ,(-sqrt(-1/t)+7)/4

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inverse of-1/((4t-7)^2)

inverse

- \frac{1}{( 4 t - 7 ) ^{2}}

\frac{- \frac{1}{t} + 7}{4}, \frac{- - \frac{1}{t} + 7}{4}

Solution steps

y = - \frac{1}{( 4 t - 7 ) ^{2}}

Replace

t

with

y

t = - \frac{1}{( 4 y - 7 ) ^{2}}

Solve for

y, t = - \frac{1}{( 4 y - 7 ) ^{2}}

\frac{- \frac{1}{t} + 7}{4}, \frac{- - \frac{1}{t} + 7}{4}

f (x) = 6 sin (x) + 7

+ ln (1 - t)

2 ln (e) (x)

f (x) = b_{1} x^{2}

f (x) = - x

What is the inverse of-1/((4t-7)^2) ?
The inverse of-1/((4t-7)^2) is (sqrt(-1/t)+7)/4 ,(-sqrt(-1/t)+7)/4