What is the inverse of (4x-1)^{(-1)}[(4(-2)-1)] ?

The inverse of (4x-1)^{(-1)}[(4(-2)-1)] is (-9+x)/(4x)

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inverse of (4x-1)^{(-1)}[(4(-2)-1)]

inverse

(4 x - 1)^{(- 1)} [(4 (- 2) - 1)]

\frac{- 9 + x}{4 x}

Solution steps

y = (4 x - 1)^{- 1} [(4 (- 2) - 1)]

Replace

x

with

y

x = (4 y - 1)^{- 1} [(4 (- 2) - 1)]

Solve for

y, x = (4 y - 1)^{- 1} [(4 (- 2) - 1)]

\frac{- 9 + x}{4 x}

f (x) = \frac{2}{( x + 3 ) ^{2}} - 1

y = \frac{2 x - 1}{3}

f (x) = e^{\frac{6 x}{100}}

f (x) = lo g_{2} (7)

f (x) = 0.35 \cdot 1 0^{- 12}

What is the inverse of (4x-1)^{(-1)}[(4(-2)-1)] ?
The inverse of (4x-1)^{(-1)}[(4(-2)-1)] is (-9+x)/(4x)