What is the inverse of sqrt(1-3x)+1-5x ?

The inverse of sqrt(1-3x)+1-5x is (-10x+7+sqrt(60x+49))/(50),(-10x+7-sqrt(60x+49))/(50)

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inverse of sqrt(1-3x)+1-5x

inverse

1 - 3 x + 1 - 5 x

\frac{- 10 x + 7 + 60 x + 49}{50}, \frac{- 10 x + 7 - 60 x + 49}{50}

Solution steps

y = 1 - 3 x + 1 - 5 x

Replace

x

with

y

x = 1 - 3 y + 1 - 5 y

Solve for

y, x = 1 - 3 y + 1 - 5 y

\frac{- 10 x + 7 + 60 x + 49}{50}, \frac{- 10 x + 7 - 60 x + 49}{50}

\frac{x ^{2} - 8}{x - 3}

f (x) = (\frac{3 x + 4}{x - 3})

f (x) = \frac{( 9 x + 10 )}{6}

f (x) = 32 - x^{2}

f (x) = \frac{3 x - 5}{x + 2}

What is the inverse of sqrt(1-3x)+1-5x ?
The inverse of sqrt(1-3x)+1-5x is (-10x+7+sqrt(60x+49))/(50),(-10x+7-sqrt(60x+49))/(50)