What is the inverse of f(x)=3x^2-4.03 ?

The inverse of f(x)=3x^2-4.03 is sqrt((x+4.03)/3),-sqrt((x+4.03)/3)

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inverse of f(x)=3x^2-4.03

inverse

f (x) = 3 x^{2} - 4.03

\frac{x + 4.03}{3}, - \frac{x + 4.03}{3}

Solution steps

y = 3 x^{2} - 4.03

Replace

x

with

y

x = 3 y^{2} - 4.03

Solve for

y, x = 3 y^{2} - 4.03

\frac{x + 4.03}{3}, - \frac{x + 4.03}{3}

\frac{x - 3}{x ^{2} - 3 x - 18}

\frac{6 + 2 x}{6 - 2 x}

y = 4 x - 3

f (x) = \frac{x + 2}{10}

f (x) = \frac{5}{x - 5} + 1

What is the inverse of f(x)=3x^2-4.03 ?
The inverse of f(x)=3x^2-4.03 is sqrt((x+4.03)/3),-sqrt((x+4.03)/3)