What is the inverse of (2x+3)^{3/5}-4 ?

The inverse of (2x+3)^{3/5}-4 is (\sqrt[3]{x^5+20x^4+160x^3+640x^2+1280x+1024}-3)/2

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inverse of (2x+3)^{3/5}-4

inverse

(2 x + 3)^{\frac{3}{5}} - 4

Solution steps

y = (2 x + 3)^{\frac{3}{5}} - 4

Replace

x

with

y

x = (2 y + 3)^{\frac{3}{5}} - 4

Solve for

y, x = (2 y + 3)^{\frac{3}{5}} - 4

sin (0.8472)

f (x) = 21 x

16 x^{2} + 1

x - 2 + 3 x

f (x) = g (x) = \frac{1}{x + 2}

What is the inverse of (2x+3)^{3/5}-4 ?
The inverse of (2x+3)^{3/5}-4 is (\sqrt[3]{x^5+20x^4+160x^3+640x^2+1280x+1024}-3)/2