What is the inverse of f(x)=20cos(5x+7) ?

The inverse of f(x)=20cos(5x+7) is (arccos(x/(20))-7)/5

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inverse of f(x)=20cos(5x+7)

inverse

f (x) = 20 cos (5 x + 7)

\frac{arccos ( \frac{x}{20} ) - 7}{5}

Solution steps

Solve for

cos (5 x + 7), y = 20 cos (5 x + 7)

cos (5 x + 7) = \frac{y}{20}

cos (a) = b \Rightarrow a = arccos (b)

5 x + 7 = arccos (\frac{y}{20})

Solve for

x, 5 x + 7 = arccos (\frac{y}{20})

\frac{arccos ( \frac{y}{20} ) - 7}{5}

Substitute

y = x

\frac{arccos ( \frac{x}{20} ) - 7}{5}

f (x) = (- 12 x - 17)^{2}

\frac{2}{s - 3}

\frac{( x ^{2} )}{4 x}

f (x) = \frac{5 x - 1}{- 3 x + 2}

f (x) = f (x) = 1 - 2 x

What is the inverse of f(x)=20cos(5x+7) ?
The inverse of f(x)=20cos(5x+7) is (arccos(x/(20))-7)/5