What is the inverse of f(x)=-2x^2-4x-5 ?

The inverse of f(x)=-2x^2-4x-5 is -(4+sqrt(-8x-24))/4 ,-(4-sqrt(-8x-24))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=-2x^2-4x-5

inverse

f (x) = - 2 x^{2} - 4 x - 5

- \frac{4 + - 8 x - 24}{4}, - \frac{4 - - 8 x - 24}{4}

Solution steps

y = - 2 x^{2} - 4 x - 5

Replace

x

with

y

x = - 2 y^{2} - 4 y - 5

Solve for

y, x = - 2 y^{2} - 4 y - 5

- \frac{4 + - 8 x - 24}{4}, - \frac{4 - - 8 x - 24}{4}

\frac{30 x + 20}{x}

4 x - 3

y = \frac{3}{4} x - \frac{3}{2}

What is the inverse of f(x)=-2x^2-4x-5 ?
The inverse of f(x)=-2x^2-4x-5 is -(4+sqrt(-8x-24))/4 ,-(4-sqrt(-8x-24))/4