What is the inverse of f(x)=x^2+9x+38 ?

The inverse of f(x)=x^2+9x+38 is (-9+sqrt(4x-71))/2 ,(-9-sqrt(4x-71))/2

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inverse of f(x)=x^2+9x+38

inverse

f (x) = x^{2} + 9 x + 38

\frac{- 9 + 4 x - 71}{2}, \frac{- 9 - 4 x - 71}{2}

Solution steps

y = x^{2} + 9 x + 38

Replace

x

with

y

x = y^{2} + 9 y + 38

Solve for

y, x = y^{2} + 9 y + 38

\frac{- 9 + 4 x - 71}{2}, \frac{- 9 - 4 x - 71}{2}

f (x) = 2 (- 3) - 3 (- 2) + 7

f (x) = \frac{2}{7 + x}

f (x) = 2 + e^{- 3 x}

sin (- \frac{12}{13})

f (x) = x^{2} + 9 x + 26

What is the inverse of f(x)=x^2+9x+38 ?
The inverse of f(x)=x^2+9x+38 is (-9+sqrt(4x-71))/2 ,(-9-sqrt(4x-71))/2