What is the inverse of f(x)=2x^2-4x+8 ?

The inverse of f(x)=2x^2-4x+8 is (4+sqrt(8x-48))/4 ,(4-sqrt(8x-48))/4

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inverse of f(x)=2x^2-4x+8

inverse

f (x) = 2 x^{2} - 4 x + 8

\frac{4 + 8 x - 48}{4}, \frac{4 - 8 x - 48}{4}

Solution steps

y = 2 x^{2} - 4 x + 8

Replace

x

with

y

x = 2 y^{2} - 4 y + 8

Solve for

y, x = 2 y^{2} - 4 y + 8

\frac{4 + 8 x - 48}{4}, \frac{4 - 8 x - 48}{4}

f (x) = 2 x^{2} - 4 x + 3

f (x) = 2 x^{2} - 4 x + 5

h (x) = \frac{3 x}{7 x - 6}

f (x) = 50 - \frac{2}{3} x

10 \cdot n - 20 n

What is the inverse of f(x)=2x^2-4x+8 ?
The inverse of f(x)=2x^2-4x+8 is (4+sqrt(8x-48))/4 ,(4-sqrt(8x-48))/4