What is the inverse of f(x)=cos(x),(1/2 , pi/3) ?

The inverse of f(x)=cos(x),(1/2 , pi/3) is arccos(x)

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inverse of f(x)=cos(x),(1/2 , pi/3)

inverse

f (x) = cos (x), (\frac{1}{2}, \frac{π}{3})

arccos (x)

Solution steps

cos (a) = b \Rightarrow a = arccos (b)

arccos (y)

Substitute

y = x

arccos (x)

y = (x - 3)^{2} - 7

f (x) = 4 x - 16

f (x) = \frac{7 x - 4}{8 x + 5}

f (x) = \frac{3}{4} (10 x - 2)

5 x^{2} - 1

What is the inverse of f(x)=cos(x),(1/2 , pi/3) ?
The inverse of f(x)=cos(x),(1/2 , pi/3) is arccos(x)