What is the inverse of f(x)=12x^8-39 ?

The inverse of f(x)=12x^8-39 is \sqrt[8]{(x+39)/(12)},-\sqrt[8]{(x+39)/(12)}

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inverse of f(x)=12x^8-39

inverse

f (x) = 12 x^{8} - 39

Solution steps

y = 12 x^{8} - 39

Replace

x

with

y

x = 12 y^{8} - 39

Solve for

y, x = 12 y^{8} - 39

f (x) = arccos (\frac{x + 1}{2})

- x^{2} + 5 x + 6

f (x) = 0.7466666

f (x) = 4 x - 11

f (x) = ln (5 - 2 x) - 3

What is the inverse of f(x)=12x^8-39 ?
The inverse of f(x)=12x^8-39 is \sqrt[8]{(x+39)/(12)},-\sqrt[8]{(x+39)/(12)}