What is the inverse of f(x)=9(-8x+8)^2+10 ?

The inverse of f(x)=9(-8x+8)^2+10 is -(sqrt(x-10)-24)/(24),-(-sqrt(x-10)-24)/(24)

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inverse of f(x)=9(-8x+8)^2+10

inverse

f (x) = 9 (- 8 x + 8)^{2} + 10

- \frac{x - 10 - 24}{24}, - \frac{- x - 10 - 24}{24}

Solution steps

y = 9 (- 8 x + 8)^{2} + 10

Replace

x

with

y

x = 9 (- 8 y + 8)^{2} + 10

Solve for

y, x = 9 (- 8 y + 8)^{2} + 10

- \frac{x - 10 - 24}{24}, - \frac{- x - 10 - 24}{24}

y = 2.5 x + 5.5

f (x) = f (x) = x - 2

f (x) = f (x) = x - 3

f (x) = \frac{8 x + 7}{x - 4}

f (x) = x^{5} = 17

What is the inverse of f(x)=9(-8x+8)^2+10 ?
The inverse of f(x)=9(-8x+8)^2+10 is -(sqrt(x-10)-24)/(24),-(-sqrt(x-10)-24)/(24)