What is the inverse of f(x)=x^2-4x-7,x<=-2 ?

The inverse of f(x)=x^2-4x-7,x<=-2 is 2+sqrt(x+11),2-sqrt(x+11)

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inverse of f(x)=x^2-4x-7,x<=-2

inverse

f (x) = x^{2} - 4 x - 7, x \leq - 2

2 + x + 11, 2 - x + 11

Solution steps

y = x^{2} - 4 x - 7

Replace

x

with

y

x = y^{2} - 4 y - 7

Solve for

y, x = y^{2} - 4 y - 7

2 + x + 11, 2 - x + 11

lo g_{7} (0.38)

1000 Q^{- \frac{1}{2}}

f (x) = f (x) = \frac{4 x - 3}{7}

f (x) = e^{5 x + 3}

f (x) = arcsec (2)

What is the inverse of f(x)=x^2-4x-7,x<=-2 ?
The inverse of f(x)=x^2-4x-7,x<=-2 is 2+sqrt(x+11),2-sqrt(x+11)