What is the inverse of y=-x^2+2x,x>-1 ?

The inverse of y=-x^2+2x,x>-1 is 1-sqrt(-x+1),sqrt(-x+1)+1

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inverse of y=-x^2+2x,x>-1

inverse

y = - x^{2} + 2 x, x > - 1

1 - - x + 1, - x + 1 + 1

Solution steps

y = - x^{2} + 2 x

Replace

x

with

y

x = - y^{2} + 2 y

Solve for

y, x = - y^{2} + 2 y

1 - - x + 1, - x + 1 + 1

f (x) = 2 (8) + 5

f (x) = \frac{2 x ^{2} - 5 x}{2}

h (x) = \frac{2}{3} x + 10

f (x) = \frac{2 x - 1}{10}

f (x) = \frac{( 4 x + 2 )}{( x + 4 )}

What is the inverse of y=-x^2+2x,x>-1 ?
The inverse of y=-x^2+2x,x>-1 is 1-sqrt(-x+1),sqrt(-x+1)+1