What is the inverse of 2cos(x),0<= x<= 2pi ?

The inverse of 2cos(x),0<= x<= 2pi is arccos(x/2)

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inverse of 2cos(x),0<= x<= 2pi

inverse

2 cos (x), 0 \leq x \leq 2 π

arccos (\frac{x}{2})

Solution steps

Solve for

cos (x), y = 2 cos (x)

cos (x) = \frac{y}{2}

cos (a) = b \Rightarrow a = arccos (b)

arccos (\frac{y}{2})

Substitute

y = x

arccos (\frac{x}{2})

f (x) = \frac{3}{( 6 - 3 x )}

h (x) = \frac{5 x}{9 x - 8}

f (x) = 5^{x^{2}}

f (x) = \frac{2 x - 2}{- 3 x + 5}

f (x) = \frac{x ^{4}}{7} + 27

What is the inverse of 2cos(x),0<= x<= 2pi ?
The inverse of 2cos(x),0<= x<= 2pi is arccos(x/2)