What is the inverse of f(x)=x^2-3x-6 ?

The inverse of f(x)=x^2-3x-6 is (3+sqrt(4x+33))/2 ,(3-sqrt(4x+33))/2

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inverse of f(x)=x^2-3x-6

inverse

f (x) = x^{2} - 3 x - 6

\frac{3 + 4 x + 33}{2}, \frac{3 - 4 x + 33}{2}

Solution steps

y = x^{2} - 3 x - 6

Replace

x

with

y

x = y^{2} - 3 y - 6

Solve for

y, x = y^{2} - 3 y - 6

\frac{3 + 4 x + 33}{2}, \frac{3 - 4 x + 33}{2}

y = - cos (0.4 t)

f (x) = \frac{x}{2 x - 1}

f (x) = \frac{7 x + 3}{8}

f (x) = x^{2} + 3

f (x) = - x^{3} + 12 x - 19

What is the inverse of f(x)=x^2-3x-6 ?
The inverse of f(x)=x^2-3x-6 is (3+sqrt(4x+33))/2 ,(3-sqrt(4x+33))/2