What is the inverse of f(x)=sqrt(x-x^2) ?

The inverse of f(x)=sqrt(x-x^2) is -(-1+sqrt(1-4x^2))/2 ,-(-1-sqrt(1-4x^2))/2

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inverse of f(x)=sqrt(x-x^2)

inverse

f (x) = x - x^{2}

- \frac{- 1 + 1 - 4 x ^{2}}{2}, - \frac{- 1 - 1 - 4 x ^{2}}{2}

Solution steps

y = x - x^{2}

Replace

x

with

y

x = y - y^{2}

Solve for

y, x = y - y^{2}

- \frac{- 1 + 1 - 4 x ^{2}}{2}, - \frac{- 1 - 1 - 4 x ^{2}}{2}

f (x) = f (2.44) = 15.72

f (x) = 42 x

f (x) = sin (x) + 1, 0 < x \leq \frac{π}{2}

e^{e^{x}} - 2

y = \frac{1}{x - 10}

What is the inverse of f(x)=sqrt(x-x^2) ?
The inverse of f(x)=sqrt(x-x^2) is -(-1+sqrt(1-4x^2))/2 ,-(-1-sqrt(1-4x^2))/2