What is the inverse of ((z-1))/((z-e^{-1))} ?

The inverse of ((z-1))/((z-e^{-1))} is (-e+z)/(e(-1+z))

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inverse of ((z-1))/((z-e^{-1))}

inverse

\frac{( z - 1 )}{( z - e ^{- 1} )}

\frac{- e + z}{e ( - 1 + z )}

Solution steps

y = \frac{z - 1}{z - e ^{- 1}}

Replace

z

with

y

z = \frac{y - 1}{y - e ^{- 1}}

Solve for

y, z = \frac{y - 1}{y - e ^{- 1}}

\frac{- e + z}{e ( - 1 + z )}

f (x) = \frac{3 x}{5}

\frac{5 - e ^{- x}}{5 + e ^{- x}}

1 1^{x}

f (x) = \frac{5 x}{9 x - 4}

What is the inverse of ((z-1))/((z-e^{-1))} ?
The inverse of ((z-1))/((z-e^{-1))} is (-e+z)/(e(-1+z))