What is the inverse of sec^2((1000000)/x) ?

The inverse of sec^2((1000000)/x) is (1000000)/(arcsec(sqrt(x))),(1000000)/(arcsec(-sqrt(x)))

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inverse of sec^2((1000000)/x)

inverse

sec^{2} (\frac{1000000}{x})

\frac{1000000}{arcsec ( x )}, \frac{1000000}{arcsec ( - x )}

Solution steps

Solve for

sec (\frac{1000000}{x}), y = sec^{2} (\frac{1000000}{x})

sec (\frac{1000000}{x}) = y, sec (\frac{1000000}{x}) = - y

sec (a) = b \Rightarrow a = arcsec (b)

\frac{1000000}{x} = arcsec (y), \frac{1000000}{x} = arcsec (- y)

Solve for

x, \frac{1000000}{x} = arcsec (y)

Solve for

x, \frac{1000000}{x} = arcsec (- y)

\frac{1000000}{arcsec ( y )}, \frac{1000000}{arcsec ( - y )}

Substitute

y = x

\frac{1000000}{arcsec ( x )}, \frac{1000000}{arcsec ( - x )}

f (x) = \frac{1 - 1}{( 1 + 0.15 \cdot 10 )}

- \frac{2}{3} x + \frac{3}{2}

f (x) = \frac{x ^{2}}{200} + \frac{x}{6}

- \frac{ln ( 5 y - 6 )}{20}

f (x) = - \frac{4}{3} x - \frac{1}{2}

What is the inverse of sec^2((1000000)/x) ?
The inverse of sec^2((1000000)/x) is (1000000)/(arcsec(sqrt(x))),(1000000)/(arcsec(-sqrt(x)))