What is the inverse of 1/(x^2+4x+4) ?

The inverse of 1/(x^2+4x+4) is (-2x+sqrt(x))/x ,-(2x+sqrt(x))/x

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inverse of 1/(x^2+4x+4)

inverse

\frac{1}{x ^{2} + 4 x + 4}

\frac{- 2 x + x}{x}, - \frac{2 x + x}{x}

Solution steps

y = \frac{1}{x ^{2} + 4 x + 4}

Replace

x

with

y

x = \frac{1}{y ^{2} + 4 y + 4}

Solve for

y, x = \frac{1}{y ^{2} + 4 y + 4}

\frac{- 2 x + x}{x}, - \frac{2 x + x}{x}

x^{23} - 3

f (x) = \frac{7 x + 9}{6 x - 7}

f (x) = 8^{2} - 15 x + 8

f (x) = \frac{4 x}{x + 9}

What is the inverse of 1/(x^2+4x+4) ?
The inverse of 1/(x^2+4x+4) is (-2x+sqrt(x))/x ,-(2x+sqrt(x))/x