What is the inverse of f(x)=sqrt(18-x^2) ?

The inverse of f(x)=sqrt(18-x^2) is sqrt(-x^2+18),-sqrt(-x^2+18)

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inverse of f(x)=sqrt(18-x^2)

inverse

f (x) = 18 - x^{2}

- x^{2} + 18, - - x^{2} + 18

Solution steps

y = 18 - x^{2}

Replace

x

with

y

x = 18 - y^{2}

Solve for

y, x = 18 - y^{2}

- x^{2} + 18, - - x^{2} + 18

csc (2)

y = 1 0^{x} - \frac{3}{2}

f (x) = \frac{2}{3 x + 1} - 1

2 (x - 4)^{2}

247 x^{23}

What is the inverse of f(x)=sqrt(18-x^2) ?
The inverse of f(x)=sqrt(18-x^2) is sqrt(-x^2+18),-sqrt(-x^2+18)