What is the inverse of f(x)=((x-2))/((4x+3)) ?

The inverse of f(x)=((x-2))/((4x+3)) is (-2-3x)/(4x-1)

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inverse of f(x)=((x-2))/((4x+3))

inverse

f (x) = \frac{( x - 2 )}{( 4 x + 3 )}

\frac{- 2 - 3 x}{4 x - 1}

Solution steps

y = \frac{x - 2}{4 x + 3}

Replace

x

with

y

x = \frac{y - 2}{4 y + 3}

Solve for

y, x = \frac{y - 2}{4 y + 3}

\frac{- 2 - 3 x}{4 x - 1}

r (x) = \frac{x}{2 x - 1}

f (x) = 2 lo g_{4} (1 - x)

f (x) = \frac{3 - 2 x}{5 x}

f (x) = \frac{( 8 x - 9 )}{2 x}

sin (\frac{7.5}{8.6})

What is the inverse of f(x)=((x-2))/((4x+3)) ?
The inverse of f(x)=((x-2))/((4x+3)) is (-2-3x)/(4x-1)