What is the inverse of (3s)/(s^2-12+30) ?

The inverse of (3s)/(s^2-12+30) is (3+3sqrt(1-8s^2))/(2s),(3-3sqrt(1-8s^2))/(2s)

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inverse of (3s)/(s^2-12+30)

inverse

\frac{3 s}{s ^{2} - 12 + 30}

\frac{3 + 3 1 - 8 s ^{2}}{2 s}, \frac{3 - 3 1 - 8 s ^{2}}{2 s}

Solution steps

y = \frac{3 s}{s ^{2} - 12 + 30}

Replace

s

with

y

s = \frac{3 y}{y ^{2} - 12 + 30}

Solve for

y, s = \frac{3 y}{y ^{2} - 12 + 30}

\frac{3 + 3 1 - 8 s ^{2}}{2 s}, \frac{3 - 3 1 - 8 s ^{2}}{2 s}

y = - 2 x

f (x) = e^{2 s i n (x)}

tan (\frac{1.2 1 ^{2}}{0.44 ( 9.8 )})

f (x) = (\frac{x ^{7} - 2}{3})^{\frac{1}{5}}

f (x) = 2 + 6 x - 2

What is the inverse of (3s)/(s^2-12+30) ?
The inverse of (3s)/(s^2-12+30) is (3+3sqrt(1-8s^2))/(2s),(3-3sqrt(1-8s^2))/(2s)