What is the inverse of f(x)=2+3(x+1)^2 ?

The inverse of f(x)=2+3(x+1)^2 is sqrt((x-2)/3)-1,-sqrt((x-2)/3)-1

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inverse of f(x)=2+3(x+1)^2

inverse

f (x) = 2 + 3 (x + 1)^{2}

\frac{x - 2}{3} - 1, - \frac{x - 2}{3} - 1

Solution steps

y = 2 + 3 (x + 1)^{2}

Replace

x

with

y

x = 2 + 3 (y + 1)^{2}

Solve for

y, x = 2 + 3 (y + 1)^{2}

\frac{x - 2}{3} - 1, - \frac{x - 2}{3} - 1

f (x) = 3. 5^{x}

f (x) = \frac{x + 2}{x + 2}

w (x) = - 20

f (x) = \frac{2 x + 5}{x + 3}

5^{x - 1}

What is the inverse of f(x)=2+3(x+1)^2 ?
The inverse of f(x)=2+3(x+1)^2 is sqrt((x-2)/3)-1,-sqrt((x-2)/3)-1