What is the inverse of f(x)=(x-3)/(7x+4) ?

The inverse of f(x)=(x-3)/(7x+4) is (-3-4x)/(7x-1)

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inverse of f(x)=(x-3)/(7x+4)

inverse

f (x) = \frac{x - 3}{7 x + 4}

\frac{- 3 - 4 x}{7 x - 1}

Solution steps

y = \frac{x - 3}{7 x + 4}

Replace

x

with

y

x = \frac{y - 3}{7 y + 4}

Solve for

y, x = \frac{y - 3}{7 y + 4}

\frac{- 3 - 4 x}{7 x - 1}

g (x) = \frac{3 x - 5}{2 + 6}

y = \frac{2}{x - 3} + 5

F (x) = \frac{( x - 1 )}{2 x + 3}

\frac{2 x ^{- 3}}{x ^{5}}

\frac{2 - x ^{2}}{2} - 3

What is the inverse of f(x)=(x-3)/(7x+4) ?
The inverse of f(x)=(x-3)/(7x+4) is (-3-4x)/(7x-1)