What is the inverse of f(x)=(x(x-3))/(x-4) ?

The inverse of f(x)=(x(x-3))/(x-4) is (3+x+sqrt(x^2-10x+9))/2 ,(3+x-sqrt(x^2-10x+9))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x(x-3))/(x-4)

inverse

f (x) = \frac{x ( x - 3 )}{x - 4}

\frac{3 + x + x ^{2} - 10 x + 9}{2}, \frac{3 + x - x ^{2} - 10 x + 9}{2}

Solution steps

y = \frac{x ( x - 3 )}{x - 4}

Replace

x

with

y

x = \frac{y ( y - 3 )}{y - 4}

Solve for

y, x = \frac{y ( y - 3 )}{y - 4}

\frac{3 + x + x ^{2} - 10 x + 9}{2}, \frac{3 + x - x ^{2} - 10 x + 9}{2}

f (x) = - \frac{2}{5} (x - 2)^{3} - 4

y = 3 (2)^{x} + 1

f (x) = \frac{x - 8}{8 x + 3}

3 ln (x + 4)

y^{2} + 1

What is the inverse of f(x)=(x(x-3))/(x-4) ?
The inverse of f(x)=(x(x-3))/(x-4) is (3+x+sqrt(x^2-10x+9))/2 ,(3+x-sqrt(x^2-10x+9))/2