What is the inverse of f(x)=((4x-3))/(x+5) ?

The inverse of f(x)=((4x-3))/(x+5) is (-3-5x)/(x-4)

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inverse of f(x)=((4x-3))/(x+5)

inverse

f (x) = \frac{( 4 x - 3 )}{x + 5}

\frac{- 3 - 5 x}{x - 4}

Solution steps

y = \frac{4 x - 3}{x + 5}

Replace

x

with

y

x = \frac{4 y - 3}{y + 5}

Solve for

y, x = \frac{4 y - 3}{y + 5}

\frac{- 3 - 5 x}{x - 4}

f (x) = \frac{3 x}{4 x - 1}

\frac{3 x}{5 x - 1}

cos (\frac{3}{- 2})

f (b) = b^{2} + 5

f (x) = 2 sin (x + 4)

What is the inverse of f(x)=((4x-3))/(x+5) ?
The inverse of f(x)=((4x-3))/(x+5) is (-3-5x)/(x-4)