What is the inverse of f(x)=0.3x^2 ?

The inverse of f(x)=0.3x^2 is sqrt((x*10)/3),-sqrt((x*10)/3)

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inverse of f(x)=0.3x^2

inverse

f (x) = 0.3 x^{2}

\frac{x \cdot 10}{3}, - \frac{x \cdot 10}{3}

Solution steps

y = 0.3 x^{2}

Replace

x

with

y

x = 0.3 y^{2}

Solve for

y, x = 0.3 y^{2}

\frac{x \cdot 10}{3}, - \frac{x \cdot 10}{3}

f (x) = arcsin (x) + \frac{π}{4}

h (x) = 200 + 4 (6)

f (x) = 3 x^{5} - 4

- 3 x^{11} + 8

f (x) = \frac{6 x + 8}{7}

What is the inverse of f(x)=0.3x^2 ?
The inverse of f(x)=0.3x^2 is sqrt((x*10)/3),-sqrt((x*10)/3)