What is the inverse of f(x)=2(x-3)^{(2)}+7 ?

The inverse of f(x)=2(x-3)^{(2)}+7 is sqrt((x-7)/2)+3,-sqrt((x-7)/2)+3

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inverse of f(x)=2(x-3)^{(2)}+7

inverse

f (x) = 2 (x - 3)^{(2)} + 7

\frac{x - 7}{2} + 3, - \frac{x - 7}{2} + 3

Solution steps

y = 2 (x - 3)^{2} + 7

Replace

x

with

y

x = 2 (y - 3)^{2} + 7

Solve for

y, x = 2 (y - 3)^{2} + 7

\frac{x - 7}{2} + 3, - \frac{x - 7}{2} + 3

f (x) = \frac{6 x}{9 x - 7}

y = \frac{1 - x}{4 x - 3}

\frac{1}{3} lo g_{10} (2 \frac{2}{3})

\frac{11}{x ^{2} + 2}

\frac{1}{8 - x}

What is the inverse of f(x)=2(x-3)^{(2)}+7 ?
The inverse of f(x)=2(x-3)^{(2)}+7 is sqrt((x-7)/2)+3,-sqrt((x-7)/2)+3