What is the inverse of y= 1/2 log_{10}(4x) ?

The inverse of y= 1/2 log_{10}(4x) is 25^x*2^{2x-2}

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inverse of y= 1/2 log_{10}(4x)

inverse

y = \frac{1}{2} lo g_{10} (4 x)

2 5^{x} \cdot 2^{2 x - 2}

Solution steps

y = \frac{1}{2} lo g_{10} (4 x)

Replace

x

with

y

x = \frac{1}{2} lo g_{10} (4 y)

Solve for

y, x = \frac{1}{2} lo g_{10} (4 y)

2 5^{x} \cdot 2^{2 x - 2}

y = ln (\frac{x + 2}{3}) + 1

361

f (x) = \frac{- x - 8}{x - 2}

tan (- \frac{1}{5})

35 x

What is the inverse of y= 1/2 log_{10}(4x) ?
The inverse of y= 1/2 log_{10}(4x) is 25^x*2^{2x-2}