What is the inverse of f(x)=-2x^2+4x+3 ?

The inverse of f(x)=-2x^2+4x+3 is -(-4+sqrt(-8x+40))/4 ,-(-4-sqrt(-8x+40))/4

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inverse of f(x)=-2x^2+4x+3

inverse

f (x) = - 2 x^{2} + 4 x + 3

- \frac{- 4 + - 8 x + 40}{4}, - \frac{- 4 - - 8 x + 40}{4}

Solution steps

y = - 2 x^{2} + 4 x + 3

Replace

x

with

y

x = - 2 y^{2} + 4 y + 3

Solve for

y, x = - 2 y^{2} + 4 y + 3

- \frac{- 4 + - 8 x + 40}{4}, - \frac{- 4 - - 8 x + 40}{4}

y = 1 + lo g_{10} (x)

lo g_{10} (\frac{y}{20})

f (x) = 300 \cdot 4 x

\frac{d}{d} y = 3 x^{2}

f (x) = 5 ln (x) + 2

What is the inverse of f(x)=-2x^2+4x+3 ?
The inverse of f(x)=-2x^2+4x+3 is -(-4+sqrt(-8x+40))/4 ,-(-4-sqrt(-8x+40))/4