What is the inverse of d/d 3x^2+4 ?

The inverse of d/d 3x^2+4 is sqrt((x-4)/3),-sqrt((x-4)/3)

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inverse of d/d 3x^2+4

inverse

\frac{d}{d} 3 x^{2} + 4

\frac{x - 4}{3}, - \frac{x - 4}{3}

Solution steps

y = \frac{d}{d} \cdot 3 x^{2} + 4

Replace

x

with

y

x = \frac{d}{d} \cdot 3 y^{2} + 4

Solve for

y, x = \frac{d}{d} 3 y^{2} + 4

\frac{x - 4}{3}, - \frac{x - 4}{3}

- \frac{2}{3} x + 4

f (x) = 1 - x + 4

3.2

3.5

- \frac{2}{3} x - 4

What is the inverse of d/d 3x^2+4 ?
The inverse of d/d 3x^2+4 is sqrt((x-4)/3),-sqrt((x-4)/3)