What is the inverse of ((x+3)^2)/(x^2-2x) ?

The inverse of ((x+3)^2)/(x^2-2x) is (-3-x+sqrt(x(x+15)))/(1-x),-(x+sqrt(x(x+15))+3)/(-x+1)

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inverse of ((x+3)^2)/(x^2-2x)

inverse

\frac{( x + 3 ) ^{2}}{x ^{2} - 2 x}

\frac{- 3 - x + x ( x + 15 )}{1 - x}, - \frac{x + x ( x + 15 ) + 3}{- x + 1}

Solution steps

y = \frac{( x + 3 ) ^{2}}{x ^{2} - 2 x}

Replace

x

with

y

x = \frac{( y + 3 ) ^{2}}{y ^{2} - 2 y}

Solve for

y, x = \frac{( y + 3 ) ^{2}}{y ^{2} - 2 y}

\frac{- 3 - x + x ( x + 15 )}{1 - x}, - \frac{x + x ( x + 15 ) + 3}{- x + 1}

f (x) = \frac{7 x - 4}{x + 3}

f (x) = \frac{( 6 x - 16 )}{- 5 x}

g (x) = \frac{x + 1}{9}

g (x) = \frac{7}{x} + 5

\frac{2}{3 s - 4}

What is the inverse of ((x+3)^2)/(x^2-2x) ?
The inverse of ((x+3)^2)/(x^2-2x) is (-3-x+sqrt(x(x+15)))/(1-x),-(x+sqrt(x(x+15))+3)/(-x+1)