What is the domain of f(x)= 9/(sqrt(x+2)) ?

The domain of f(x)= 9/(sqrt(x+2)) is x>-2

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domain of f(x)= 9/(sqrt(x+2))

domain

f (x) = \frac{9}{x + 2}

x > - 2

Interval Notation

(- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x > - 2

f (x) = 16 + x^{2} - x + 1

f (x) = - 2^{x} + 1

f (x) = \frac{x ^{2}}{x ^{2} - 9}

f (x) = x^{2} - 4 x + 1, x < 2

f (x) = \frac{8 x + 3}{8 - 3 x}

What is the domain of f(x)= 9/(sqrt(x+2)) ?
The domain of f(x)= 9/(sqrt(x+2)) is x>-2