What is the inverse of f(y)=sqrt(y-y^2) ?

The inverse of f(y)=sqrt(y-y^2) is -(-1+sqrt(1-4y^2))/2 ,-(-1-sqrt(1-4y^2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(y)=sqrt(y-y^2)

inverse

f (y) = y - y^{2}

- \frac{- 1 + 1 - 4 y ^{2}}{2}, - \frac{- 1 - 1 - 4 y ^{2}}{2}

Solution steps

y = y - y^{2}

Replace

y

with

y

y = y - y^{2}

Solve for

y, y = y - y^{2}

- \frac{- 1 + 1 - 4 y ^{2}}{2}, - \frac{- 1 - 1 - 4 y ^{2}}{2}

f (x) = - x^{2} + 3 x - 2, x = - 2

2 π (x)^{2} + 8 π (x)

f (x) = - 5000 x + 60000

f (x) = 5 + 3 e^{(2 x)}

f (x) = 3 x^{3} - 13

What is the inverse of f(y)=sqrt(y-y^2) ?
The inverse of f(y)=sqrt(y-y^2) is -(-1+sqrt(1-4y^2))/2 ,-(-1-sqrt(1-4y^2))/2