What is the inverse of y=(4-3x)^2 ?

The inverse of y=(4-3x)^2 is -(sqrt(x)-4)/3 ,-(-sqrt(x)-4)/3

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inverse of y=(4-3x)^2

inverse

y = (4 - 3 x)^{2}

- \frac{x - 4}{3}, - \frac{- x - 4}{3}

Solution steps

y = (4 - 3 x)^{2}

Replace

x

with

y

x = (4 - 3 y)^{2}

Solve for

y, x = (4 - 3 y)^{2}

- \frac{x - 4}{3}, - \frac{- x - 4}{3}

f (x) = 2 e^{x} + 1

f (x) = lo g_{3} (2 x - 2) + 1

f (x) = \frac{2 - x}{x + 5} - 3

f (x) = \frac{x + 3}{2 x - 5}

f (x) = 0.00893 - 0.004

What is the inverse of y=(4-3x)^2 ?
The inverse of y=(4-3x)^2 is -(sqrt(x)-4)/3 ,-(-sqrt(x)-4)/3